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You will need scratch paper to do this lesson.
You have a balanced scale. On one side of the scale are three equally heavy sacks of barley and a 1-pound weight, and on the other side is a 10-pound weight. Since the scale balances, the two sides weigh the same amount. If $b$ represents the weight of a sack of barley in pounds, the objects on this scale obey the equation $3b+1=10$.
Solve this equation to find the weight of a single sack of barley, and check your solution.
Solve the equation you found in scaleqn, and check your solution.
Each row of the table below lists some weights and equally-heavy objects that are on a balanced scale. Write down an equation that the objects on the scale obey. Then solve it and check your solution by using scratch paper or the grids to the left.
The senior class of Mathscribe High is planning a party. They have \$500 that they can spend. It costs \$100 to rent the school gym for the party, and they can buy bottles of soda for \$2 each. They want to spend all their money on soda except what it costs to rent the gym. If $s$ represents the number of bottles of soda they can buy, an equation for $s$ is $2s+100=500$.
By solving this equation, find the number of bottles of soda the seniors can buy. Check your solution.
There are two common ways to measure temperature: in degrees Celsius, and in degrees Fahrenheit. If $C$ represents the current temperature in degrees Celsius and $F$ represents the current temperature in degrees Fahrenheit, then you can convert between them with the equation:
Convert each temperature in the table below from degrees Celsius into degrees Fahrenheit.
If the current temperature is 68 degrees Fahrenheit, an equation for the current temperature in degrees Celsius is $$9/5 C + 32 = 68$$. Solve this equation, and check your solution.
Each row of this table gives a temperature in degrees Fahrenheit. Write an equation for the corresponding temperature in degrees Celsius, and then solve it as you did in FtoCqn. Use scratch paper.